Formula q_851 (Q658): Difference between revisions

Latest revision as of 13:25, 20 April 2020

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English	Formula q_851	No description defined

q_851

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\forall n\in {\mathbb {N}}:(\sum _{i=1}^{n}a_{i})(\sum _{i=1}^{n}{\frac {1}{a_{i}}})\geq n^{2}

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Revision as of 13:24, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: arqmath formula id (P8): q_851 ← Older edit	Latest revision as of 13:25, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: Defining formula (P1): \forall n \in \Bbb{N} : (\sum_{i=1}^{n} a_{i} ) (\sum_{i=1}^{n} \frac{1}{a_{i}} ) \ge n^2
	Property / Defining formula
		$\forall n\in {\mathbb {N}}:(\sum _{i=1}^{n}a_{i})(\sum _{i=1}^{n}{\frac {1}{a_{i}}})\geq n^{2}$ `\forall n \in \Bbb{N} : (\sum_{i=1}^{n} a_{i} ) (\sum_{i=1}^{n} \frac{1}{a_{i}} ) \ge n^2`
	Property / Defining formula: $\forall n\in {\mathbb {N}}:(\sum _{i=1}^{n}a_{i})(\sum _{i=1}^{n}{\frac {1}{a_{i}}})\geq n^{2}$ / rank
		Normal rank