Formula q_282 (Q951): Difference between revisions

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Created claim: arqmath formula id (P8): q_282
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Created claim: Defining formula (P1): 4 \downarrow 3 = 4 \downarrow \downarrow (4 \downarrow \downarrow 4) = 4 \downarrow \downarrow (4 + 1) = (4 + 1) + 1 = 6 = 4 + 3 - 1
 
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4 \downarrow 3 = 4 \downarrow \downarrow (4 \downarrow \downarrow 4) = 4 \downarrow \downarrow (4 + 1) = (4 + 1) + 1 = 6 = 4 + 3 - 1
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Latest revision as of 18:29, 22 April 2020

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