Topic B.1 (manual reference) (Q1023): Difference between revisions

@@ Property / relevant answers @@
-2760112
@@ Property / relevant answers: 2760112 / rank @@
-Normal rank
@@ Property / relevant answers: 2760112 / reference @@
-Defining formula:  $f'(x)={\frac {x^{2}-c}{(x^{2}+2x+c)^{2}}}=0\implies x=\pm {\sqrt {c}}$ 
f'(x)=\frac{x^2-c}{(x^2+2x+c)^2}=0 \implies x=\pm \sqrt c

Latest revision as of 10:04, 29 April 2020