Q1030 (Q1030): Difference between revisions

@@ Property / math stackexcange post id @@
+3145414
@@ Property / math stackexcange post id: 3145414 / rank @@
+Normal rank
@@ Property / relevant answers @@
+3145425
@@ Property / relevant answers: 3145425 / rank @@
+Normal rank
@@ Property / relevant answers: 3145425 / qualifier @@
+Defining formula:  $\sum _{n=0}^{N}nx^{n}=x\sum _{n=0}^{N}nx^{n-1}=x\sum _{n=0}^{N}{\frac {d}{dx}}x^{n}=x{\frac {d}{dx}}\sum _{n=0}^{N}x^{n}=x{\frac {d}{dx}}{\frac {x^{N+1}-1}{x-1}}$ 
\sum_{n=0}^{N}nx^n=x\sum_{n=0}^{N}nx^{n-1}=x\sum_{n=0}^{N}\frac{d}{dx}x^{n}=x\frac{d}{dx}\sum_{n=0}^{N}x^{n}=x\frac{d}{dx}\frac{x^{N+1}-1}{x-1}

Latest revision as of 12:35, 29 April 2020