Q1188 (Q1188): Difference between revisions

@@ Property / math stackexcange post id @@
+3080329
@@ Property / math stackexcange post id: 3080329 / rank @@
+Normal rank
@@ Property / relevant answers @@
+3080331
@@ Property / relevant answers: 3080331 / rank @@
+Normal rank
@@ Property / relevant answers: 3080331 / qualifier @@
+Defining formula:  $\sum _{k=0}^{n}k{\binom {n}{k}}=n2^{n-1}=2^{n-1+\log _{2}n}$ 
\sum_{k=0}^n k\binom nk=n2^{n-1}=2^{n-1+\log_2n}

Latest revision as of 16:14, 20 May 2020