Formula q_342 (Q240): Difference between revisions

Latest revision as of 13:02, 20 April 2020

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English	Formula q_342	No description defined

q_342

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e^{x}={\frac {\sinh \pi }{\pi }}+{\frac {2\sinh \pi }{\pi }}\sum _{n\geq 1}{\frac {(-1)^{n}}{n^{2}+1}}(\cos nx-n\sin nx)

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Revision as of 13:02, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: arqmath formula id (P8): q_342 ← Older edit	Latest revision as of 13:02, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: Defining formula (P1): e^x=\frac{\sinh\pi}\pi+\frac{2\sinh\pi}\pi\sum_{n\geq1}\frac{(-1)^n}{n^2+1}(\cos nx-n\sin nx)
	Property / Defining formula
		$e^{x}={\frac {\sinh \pi }{\pi }}+{\frac {2\sinh \pi }{\pi }}\sum _{n\geq 1}{\frac {(-1)^{n}}{n^{2}+1}}(\cos nx-n\sin nx)$ `e^x=\frac{\sinh\pi}\pi+\frac{2\sinh\pi}\pi\sum_{n\geq1}\frac{(-1)^n}{n^2+1}(\cos nx-n\sin nx)`
	Property / Defining formula: $e^{x}={\frac {\sinh \pi }{\pi }}+{\frac {2\sinh \pi }{\pi }}\sum _{n\geq 1}{\frac {(-1)^{n}}{n^{2}+1}}(\cos nx-n\sin nx)$ / rank
		Normal rank