Formula q_345 (Q243): Difference between revisions

Latest revision as of 13:02, 20 April 2020

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English	Formula q_345	No description defined

q_345

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e^{\pi }={\frac {\sinh \pi }{\pi }}+{\frac {2\sinh \pi }{\pi }}\sum _{n\geq 1}{\frac {(-1)^{n}}{n^{2}+1}}((-1)^{n}-n\cdot 0)

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Revision as of 13:02, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: arqmath formula id (P8): q_345 ← Older edit	Latest revision as of 13:02, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: Defining formula (P1): e^\pi=\frac{\sinh\pi}\pi+\frac{2\sinh\pi}\pi\sum_{n\geq1}\frac{(-1)^n}{n^2+1}((-1)^n-n\cdot0)
	Property / Defining formula
		$e^{\pi }={\frac {\sinh \pi }{\pi }}+{\frac {2\sinh \pi }{\pi }}\sum _{n\geq 1}{\frac {(-1)^{n}}{n^{2}+1}}((-1)^{n}-n\cdot 0)$ `e^\pi=\frac{\sinh\pi}\pi+\frac{2\sinh\pi}\pi\sum_{n\geq1}\frac{(-1)^n}{n^2+1}((-1)^n-n\cdot0)`
	Property / Defining formula: $e^{\pi }={\frac {\sinh \pi }{\pi }}+{\frac {2\sinh \pi }{\pi }}\sum _{n\geq 1}{\frac {(-1)^{n}}{n^{2}+1}}((-1)^{n}-n\cdot 0)$ / rank
		Normal rank