Formula q_468 (Q324): Difference between revisions

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Created claim: arqmath formula id (P8): q_468
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Created claim: Defining formula (P1): \displaystyle \sum_{r=0}^n {n+r\choose r} \frac{1}{2^{r}}= 2^{n}
 
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\displaystyle \sum_{r=0}^n {n+r\choose r} \frac{1}{2^{r}}= 2^{n}
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Latest revision as of 13:06, 20 April 2020

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