Formula q_24 (Q1033): Difference between revisions

Latest revision as of 16:34, 24 April 2020

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English	Formula q_24	No description defined

q_24

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P((2)|(1))={\frac {P((2)\cap (1))}{P((1))}}={\frac {P((2))P((1))}{P((1))}}=P((2))

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Revision as of 16:34, 24 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: arqmath formula id (P8): q_24 ← Older edit	Latest revision as of 16:34, 24 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: Defining formula (P1): P((2)\|(1))=\frac{P((2) \cap (1))}{P((1))}=\frac{P((2))P((1))}{P((1))} = P((2))
	Property / Defining formula
		$P((2)\|(1))={\frac {P((2)\cap (1))}{P((1))}}={\frac {P((2))P((1))}{P((1))}}=P((2))$ `P((2)\|(1))=\frac{P((2) \cap (1))}{P((1))}=\frac{P((2))P((1))}{P((1))} = P((2))`
	Property / Defining formula: $P((2)\|(1))={\frac {P((2)\cap (1))}{P((1))}}={\frac {P((2))P((1))}{P((1))}}=P((2))$ / rank
		Normal rank