Q1199 (Q1199): Difference between revisions

@@ Property / relevant answers @@
+3081357
@@ Property / relevant answers: 3081357 / rank @@
+Normal rank
@@ Property / relevant answers: 3081357 / qualifier @@
+Defining formula:  ${\frac {\sum _{i=1}^{n}a_{i}}{n}}\geq {\frac {n}{\sum _{i=1}^{n}{\frac {1}{a_{i}}}}}$ 
\frac{\sum_{i=1}^n a_i}{n}\geq \frac{n}{\sum_{i=1}^n\frac{1}{a_i}}

Latest revision as of 16:15, 20 May 2020