Formula q_314 (Q223): Difference between revisions

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Created claim: Defining formula (P1): g(x) = f^{-1}\circ g\circ f =\frac{g(\frac{2x}{1-x})}{2+g(\frac{2x}{1-x})},
 
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g(x) = f^{-1}\circ g\circ f =\frac{g(\frac{2x}{1-x})}{2+g(\frac{2x}{1-x})},
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