Formula q_344 (Q242): Difference between revisions

Latest revision as of 13:02, 20 April 2020

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English	Formula q_344	No description defined

q_344

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e^{\pi }={\frac {\sinh \pi }{\pi }}+{\frac {2\sinh \pi }{\pi }}\sum _{n\geq 1}{\frac {(-1)^{n}}{n^{2}+1}}(\cos n\pi -n\sin n\pi )

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Revision as of 13:02, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: arqmath formula id (P8): q_344 ← Older edit	Latest revision as of 13:02, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: Defining formula (P1): e^\pi=\frac{\sinh\pi}\pi+\frac{2\sinh\pi}\pi\sum_{n\geq1}\frac{(-1)^n}{n^2+1}(\cos n\pi-n\sin n\pi)
	Property / Defining formula
		$e^{\pi }={\frac {\sinh \pi }{\pi }}+{\frac {2\sinh \pi }{\pi }}\sum _{n\geq 1}{\frac {(-1)^{n}}{n^{2}+1}}(\cos n\pi -n\sin n\pi )$ `e^\pi=\frac{\sinh\pi}\pi+\frac{2\sinh\pi}\pi\sum_{n\geq1}\frac{(-1)^n}{n^2+1}(\cos n\pi-n\sin n\pi)`
	Property / Defining formula: $e^{\pi }={\frac {\sinh \pi }{\pi }}+{\frac {2\sinh \pi }{\pi }}\sum _{n\geq 1}{\frac {(-1)^{n}}{n^{2}+1}}(\cos n\pi -n\sin n\pi )$ / rank
		Normal rank