Formula q_871 (Q678): Difference between revisions

Latest revision as of 13:26, 20 April 2020

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English	Formula q_871	No description defined

q_871

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{\big (}\sum _{i=1}^{1}a_{i}{\big )}{\big (}\sum _{i=1}^{1}{\frac {1}{a_{i}}}{\big )}=a_{1}{\frac {1}{a_{1}}}=1=1^{2}

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Revision as of 13:25, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: arqmath formula id (P8): q_871 ← Older edit	Latest revision as of 13:26, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: Defining formula (P1): \big(\sum_{i=1}^{1}a_{i}\big) \big(\sum_{i=1}^{1} \frac{1}{a_{i}}\big) = a_{1} \frac{1}{a_{1}} = 1 = 1^2
	Property / Defining formula
		${\big (}\sum _{i=1}^{1}a_{i}{\big )}{\big (}\sum _{i=1}^{1}{\frac {1}{a_{i}}}{\big )}=a_{1}{\frac {1}{a_{1}}}=1=1^{2}$ `\big(\sum_{i=1}^{1}a_{i}\big) \big(\sum_{i=1}^{1} \frac{1}{a_{i}}\big) = a_{1} \frac{1}{a_{1}} = 1 = 1^2`
	Property / Defining formula: ${\big (}\sum _{i=1}^{1}a_{i}{\big )}{\big (}\sum _{i=1}^{1}{\frac {1}{a_{i}}}{\big )}=a_{1}{\frac {1}{a_{1}}}=1=1^{2}$ / rank
		Normal rank