Formula q_874 (Q681): Difference between revisions

Latest revision as of 13:26, 20 April 2020

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English	Formula q_874	No description defined

q_874

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\left(\sum _{i=1}^{n+1}a_{i}\right)\left(\sum _{i=1}^{n+1}{\frac {1}{a_{i}}}\right)=\left[\left(\sum _{i=1}^{n}a_{i}\right)+a_{n+1}\right]\left[\left(\sum _{i=1}^{n}{\frac {1}{a_{i}}}\right)+{\frac {1}{a_{n+1}}}\right]

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Revision as of 13:26, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: arqmath formula id (P8): q_874 ← Older edit	Latest revision as of 13:26, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: Defining formula (P1): \left(\sum_{i=1}^{n+1}a_{i}\right) \left(\sum_{i=1}^{n+1} \frac{1}{a_{i}}\right) = \left[\left(\sum_{i=1}^{n}a_{i}\right) + a_{n+1}\right] \left[\left(\sum_{i=1}^{n} \frac{1}{a_{i}}\right) + \frac{1}{a_{n+1}}\right]
	Property / Defining formula
		$\left(\sum _{i=1}^{n+1}a_{i}\right)\left(\sum _{i=1}^{n+1}{\frac {1}{a_{i}}}\right)=\left[\left(\sum _{i=1}^{n}a_{i}\right)+a_{n+1}\right]\left[\left(\sum _{i=1}^{n}{\frac {1}{a_{i}}}\right)+{\frac {1}{a_{n+1}}}\right]$ `\left(\sum_{i=1}^{n+1}a_{i}\right) \left(\sum_{i=1}^{n+1} \frac{1}{a_{i}}\right) = \left[\left(\sum_{i=1}^{n}a_{i}\right) + a_{n+1}\right] \left[\left(\sum_{i=1}^{n} \frac{1}{a_{i}}\right) + \frac{1}{a_{n+1}}\right]`
	Property / Defining formula: $\left(\sum _{i=1}^{n+1}a_{i}\right)\left(\sum _{i=1}^{n+1}{\frac {1}{a_{i}}}\right)=\left[\left(\sum _{i=1}^{n}a_{i}\right)+a_{n+1}\right]\left[\left(\sum _{i=1}^{n}{\frac {1}{a_{i}}}\right)+{\frac {1}{a_{n+1}}}\right]$ / rank
		Normal rank