Q1206 (Q1206): Difference between revisions

@@ Property / relevant answers @@
+https://math.stackexchange.com/a/408304
@@ Property / relevant answers: https://math.stackexchange.com/a/408304 / rank @@
+Normal rank
+Defining formula:  $\int {\frac {\ln(1+x)\ln(1-x)\,dx}{1+x}}={\frac {\ln 2}{2}}\ln ^{2}(1+x)-\ln(1+x)\,\mathrm {Li} _{2}\left({\frac {1+x}{2}}\right)+\mathrm {Li} _{3}\left({\frac {1+x}{2}}\right)$ 
\int\frac{\ln(1+x)\ln(1-x)\,dx}{1+x}=\frac{\ln2}{2}\ln^2(1+x)-\ln(1+x)\,\mathrm{Li}_2\left(\frac{1+x}{2}\right)+\mathrm{Li}_3\left(\frac{1+x}{2}\right)

Revision as of 12:44, 14 May 2020