Q1154 (Q1154): Difference between revisions

@@ Property / relevant answers @@
+https://math.stackexchange.com/a/3116545
@@ Property / relevant answers: https://math.stackexchange.com/a/3116545 / rank @@
+Normal rank
+Defining formula:  $\tan \theta ={\dfrac {1}{\tan(\pi /2-\theta )}}$ 
\tan \theta = \dfrac {1}{\tan (\pi/2 - \theta)}
+Defining formula:  $\tan 2\theta ={\dfrac {2\tan \theta }{1-\tan ^{2}\theta }}$ 
\tan 2 \theta = \dfrac {2 \tan \theta}{1-\tan^2 \theta}

Revision as of 14:37, 13 May 2020