Q1171 (Q1171): Difference between revisions
Jump to navigation
Jump to search
Changed an Item |
Created claim: relevant answers (P14): 17973 |
||
| Property / relevant answers | |||
| Property / relevant answers: 17973 / rank | |||
Normal rank | |||
| Property / relevant answers: 17973 / qualifier | |||
Defining formula: \sin(a)\sin\Bigl(\frac{d}{2}\Bigr) = \frac{1}{2} \cdot \biggl[ \cos\Bigl(a-\frac{d}{2}\Bigr) - \cos\Bigl(a+\frac{d}{2}\Bigr)\biggr]$$ and $$\sin(a+d) \cdot \sin\Bigl(\frac{d}{2}\Bigr) = \frac{1}{2} \cdot \biggl[ \cos\Bigl(a + d -\frac{d}{2}\Bigr) - \cos\Bigl(a+d+\frac{d}{2}\Bigr) \biggr] | |||
![{\displaystyle \sin(a)\sin {\Bigl (}{\frac {d}{2}}{\Bigr )}={\frac {1}{2}}\cdot {\biggl [}\cos {\Bigl (}a-{\frac {d}{2}}{\Bigr )}-\cos {\Bigl (}a+{\frac {d}{2}}{\Bigr )}{\biggr ]}\$\$and\$\$\sin(a+d)\cdot \sin {\Bigl (}{\frac {d}{2}}{\Bigr )}={\frac {1}{2}}\cdot {\biggl [}\cos {\Bigl (}a+d-{\frac {d}{2}}{\Bigr )}-\cos {\Bigl (}a+d+{\frac {d}{2}}{\Bigr )}{\biggr ]}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/6436b7cff15fc800a6cd99bae83825b859a25a57)
Latest revision as of 13:45, 20 May 2020
No description defined
| Language | Label | Description | Also known as |
|---|---|---|---|
| English | No label defined |
No description defined |
Statements
B.70
0 references
q_643
0 references