Q1278 (Q1278): Difference between revisions

@@ Property / relevant answers @@
+https://math.stackexchange.com/a/705071
@@ Property / relevant answers: https://math.stackexchange.com/a/705071 / rank @@
+Normal rank
+Defining formula:  $x+{\frac {1}{x}}-2={\frac {x^{2}}{x}}+{\frac {1}{x}}-{\frac {2x}{x}}={\frac {x^{2}-2x+1}{x}}={\frac {\left(x-1\right)^{2}}{x}}\geq 0$ 
x+\frac{1}{x}-2 = \frac{x^2}x+\frac1x-\frac{2x}x= \frac{x^2-2x+1}{x} = \frac{\left(x-1\right)^2}{x} \geq 0

Revision as of 15:58, 13 May 2020