Q1278 (Q1278): Difference between revisions

From ArqMath20

Jump to navigation Jump to search

← Older editNewer edit →

Revision as of 16:07, 14 May 2020 Admin (talk | contribs) Bureaucrats, Interface administrators, Administrators 199 edits ‎Changed claim: relevant answers (P14): https://math.stackexchange.com/a/705071 ← Older edit		Revision as of 16:07, 14 May 2020 Admin (talk | contribs) Bureaucrats, Interface administrators, Administrators 199 edits ‎Changed claim: relevant answers (P14): https://math.stackexchange.com/a/3196161 Newer edit →
		Property / relevant answers: https://math.stackexchange.com/a/3196161 / reference
			our score: 2 Amount 2 Unit 1

---

Revision as of 16:07, 14 May 2020

No description defined

Language	Label	Description	Also known as
English	No label defined	No description defined

Statements

math-stackexchange-category

functions

0 references

elementary-set-theory

0 references

topic-id

A.74

0 references

post type

Question

0 references

math stackexcange post id

3196153

0 references

relevant answers

https://math.stackexchange.com/a/3196161

Defining formula

${\displaystyle x+{1 \over x}\geq 2}$

1 reference

our score

2

https://math.stackexchange.com/a/705071

Defining formula

${\displaystyle x+{\frac {1}{x}}-2={\frac {x^{2}}{x}}+{\frac {1}{x}}-{\frac {2x}{x}}={\frac {x^{2}-2x+1}{x}}={\frac {\left(x-1\right)^{2}}{x}}\geq 0}$

1 reference

our score

1

 

Sitelinks

Wikipedia(0 entries)

Retrieved from "https://arq20.formulasearchengine.com/index.php?title=Item:Q1278&oldid=4626"