Formula q_314 (Q223): Difference between revisions

Latest revision as of 13:01, 20 April 2020

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English	Formula q_314	No description defined

q_314

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g(x)=f^{-1}\circ g\circ f={\frac {g({\frac {2x}{1-x}})}{2+g({\frac {2x}{1-x}})}},

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Revision as of 13:01, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: arqmath formula id (P8): q_314 ← Older edit	Latest revision as of 13:01, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: Defining formula (P1): g(x) = f^{-1}\circ g\circ f =\frac{g(\frac{2x}{1-x})}{2+g(\frac{2x}{1-x})},
	Property / Defining formula
		$g(x)=f^{-1}\circ g\circ f={\frac {g({\frac {2x}{1-x}})}{2+g({\frac {2x}{1-x}})}},$ `g(x) = f^{-1}\circ g\circ f =\frac{g(\frac{2x}{1-x})}{2+g(\frac{2x}{1-x})},`
	Property / Defining formula: $g(x)=f^{-1}\circ g\circ f={\frac {g({\frac {2x}{1-x}})}{2+g({\frac {2x}{1-x}})}},$ / rank
		Normal rank