Q1188 (Q1188): Difference between revisions

@@ Property / relevant answers @@
+https://math.stackexchange.com/a/3080331
@@ Property / relevant answers: https://math.stackexchange.com/a/3080331 / rank @@
+Normal rank
+Defining formula:  $\sum _{k=0}^{n}k{\binom {n}{k}}=n2^{n-1}=2^{n-1+\log _{2}n}$ 
\sum_{k=0}^n k\binom nk=n2^{n-1}=2^{n-1+\log_2n}

Revision as of 14:05, 13 May 2020