Q1123 (Q1123): Difference between revisions

${\displaystyle \int {\frac {\ln(1+x)\ln(1-x)\,dx}{1+x}}={\frac {\ln 2}{2}}\ln ^{2}(1+x)-\ln(1+x)\,\mathrm {Li} _{2}\left({\frac {1+x}{2}}\right)+\mathrm {Li} _{3}\left({\frac {1+x}{2}}\right)}$