Q1150 (Q1150): Difference between revisions

@@ Property / relevant answers @@
+3058291
@@ Property / relevant answers: 3058291 / rank @@
+Normal rank
@@ Property / relevant answers: 3058291 / qualifier @@
+Defining formula:  $e^{\pi }={\frac {\sinh \pi }{\pi }}+{\frac {2\sinh \pi }{\pi }}\sum _{n\geq 1}{\frac {(-1)^{n}}{n^{2}+1}}(\cos n\pi -n\sin n\pi )$ 
e^\pi=\frac{\sinh\pi}\pi+\frac{2\sinh\pi}\pi\sum_{n\geq1}\frac{(-1)^n}{n^2+1}(\cos n\pi-n\sin n\pi)

Latest revision as of 09:17, 20 May 2020