Q1278 (Q1278): Difference between revisions

${\displaystyle x+{\frac {1}{x}}-2={\frac {x^{2}}{x}}+{\frac {1}{x}}-{\frac {2x}{x}}={\frac {x^{2}-2x+1}{x}}={\frac {\left(x-1\right)^{2}}{x}}\geq 0}$