Formula q_468 (Q324)

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Revision as of 13:06, 20 April 2020 by SchuBot (talk | contribs) (‎Created claim: Defining formula (P1): \displaystyle \sum_{r=0}^n {n+r\choose r} \frac{1}{2^{r}}= 2^{n})
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Formula q_468
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