No label defined (Q1279)
No description defined
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Statements
A.71
0 references
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![{\displaystyle 1^{2}+\ldots +p^{2}+(p+1)^{2}={\frac {p(p+1)(2p+1)}{6}}+(p+1)^{2}={\frac {p+1}{6}}\left[p(2p+1)+6(p+1)\right]={\frac {p+1}{6}}\left[2p^{2}+8p+6\right]={\frac {(p+1)(p+2)(2p+3)}{6}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/833b59bd657ff62c2b6c76586804439d904e1256)