Q1250 (Q1250): Difference between revisions

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‎Created claim: relevant answers (P14): https://math.stackexchange.com/a/16837
‎Changed claim: relevant answers (P14): 16837
Property / relevant answersProperty / relevant answers

Revision as of 16:12, 14 May 2020

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    Statements

    topic-id
    A.46
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    post type
    Question
    0 references
    relevant answers
    16837
    Defining formula
    ∫01f(x)xpn(x)dx=∫01f×(p−xf+xf)dx=∫01xf(x)2dx+∫01f×(p−xf)dx
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