Formula q_876 (Q683): Difference between revisions

Latest revision as of 13:26, 20 April 2020

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English	Formula q_876	No description defined

q_876

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= (\sum_{i = 1}^{n} a_{i}) (\sum_{i = 1}^{n} \frac{1}{a_{i}}) + (\sum_{i = 1}^{n} a_{i}) \frac{1}{a_{n + 1}} + a_{n + 1} (\sum_{i = 1}^{n} \frac{1}{a_{i}}) + a_{n + 1} \frac{1}{a_{n + 1}}

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Revision as of 13:26, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: arqmath formula id (P8): q_876 ← Older edit	Latest revision as of 13:26, 20 April 2020 SchuBot (talk \| contribs) SchuBot, Bots, Bureaucrats, flow-bot, Suppressors, Administrators 4,665 edits ‎Created claim: Defining formula (P1): =\left(\sum_{i=1}^{n}a_{i}\right)\left(\sum_{i=1}^{n} \frac{1}{a_{i}}\right) +\left(\sum_{i=1}^{n}a_{i}\right) \frac{1}{a_{n+1}} + a_{n+1} \left(\sum_{i=1}^{n} \frac{1}{a_{i}}\right) +a_{n+1} \frac{1}{a_{n+1}}
	Property / Defining formula
		$= (\sum_{i = 1}^{n} a_{i}) (\sum_{i = 1}^{n} \frac{1}{a_{i}}) + (\sum_{i = 1}^{n} a_{i}) \frac{1}{a_{n + 1}} + a_{n + 1} (\sum_{i = 1}^{n} \frac{1}{a_{i}}) + a_{n + 1} \frac{1}{a_{n + 1}}$ `=\left(\sum_{i=1}^{n}a_{i}\right)\left(\sum_{i=1}^{n} \frac{1}{a_{i}}\right) +\left(\sum_{i=1}^{n}a_{i}\right) \frac{1}{a_{n+1}} + a_{n+1} \left(\sum_{i=1}^{n} \frac{1}{a_{i}}\right) +a_{n+1} \frac{1}{a_{n+1}}`
	Property / Defining formula: $= (\sum_{i = 1}^{n} a_{i}) (\sum_{i = 1}^{n} \frac{1}{a_{i}}) + (\sum_{i = 1}^{n} a_{i}) \frac{1}{a_{n + 1}} + a_{n + 1} (\sum_{i = 1}^{n} \frac{1}{a_{i}}) + a_{n + 1} \frac{1}{a_{n + 1}}$ / rank
		Normal rank