Q1029 (Q1029): Difference between revisions

From ArqMath20
Jump to navigation Jump to search
← Older edit

Scharpf (talk | contribs)

311 edits
Scharpf (talk | contribs)
311 edits
‎Changed claim: relevant answers (P14): 3142760
Scharpf (talk | contribs)
311 edits
‎Changed claim: relevant answers (P14): 3142760
 
Property / relevant answers: 3142760 / qualifier
Defining formula:

limn→∞(27)n(n!)3(3n)!n=1

\lim_{n\rightarrow \infty}\sqrt[n]{\frac{(27)^n(n!)^3}{(3n)!}} = 1
 

Latest revision as of 08:48, 6 May 2020

No description defined
Language Label Description Also known as
English
No label defined
No description defined

    Statements

    topic-id
    B.8
    0 references
    arqmath formula id
    q_49
    0 references
    post type
    Question
    0 references
    relevant answers
    3142760
    Defining formula
    (27)n(n!)3(3n)!n∼((27)n(2πn(ne)n)36πn(3ne)3n)1n=272π3nn32n(ne)36π1nn12n(3e)3n3=(2πn3)1n
    0 references
     
      Retrieved from "https://arq20.formulasearchengine.com/w/index.php?title=Item:Q1029&oldid=4516"