Q1278 (Q1278): Difference between revisions

+our score: 2Amount 2
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Revision as of 16:07, 14 May 2020

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English	No label defined	No description defined

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A.74

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x + \frac{1}{x} \geq 2

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x + \frac{1}{x} - 2 = \frac{x^{2}}{x} + \frac{1}{x} - \frac{2 x}{x} = \frac{x^{2} - 2 x + 1}{x} = \frac{{(x - 1)}^{2}}{x} \geq 0

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