Q1278 (Q1278): Difference between revisions

@@ Property / relevant answers: 3196161 / qualifier @@
-Defining formula:  $x + \frac{1}{x} \geq 2$ 
x+{1\over x}\geq 2
@@ Property / relevant answers: 3196161 / reference @@
-our score: 2Amount 2
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Revision as of 13:50, 20 May 2020

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A.74

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x + \frac{1}{x} - 2 = \frac{x^{2}}{x} + \frac{1}{x} - \frac{2 x}{x} = \frac{x^{2} - 2 x + 1}{x} = \frac{{(x - 1)}^{2}}{x} \geq 0

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